Example (cont.)
The total heat transfer through the handle can be calculated also. qf=Mtanh(mL)=8.325*tanh(3.138*0.2)=4.632(W)
Very small amount: latent heat of evaporation for water: 2257 kJ/kg. Therefore, the amount of heat loss is just enough to vaporize 0.007 kg of water in one hour.
If a stainless steel handle is used instead, what will happen:
For a stainless steel, the thermal conductivity k=15 W/m°C.
Use the same parameter as before: