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5.142 (a)
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5.142 (a), §1
5.142 (a), §2 Solution
The arbitrary vector
can be expressed as
so
So
Since
the transformation matrix
Q
from
S
to
E
is
So
So
a
'=-5
a
+3
b
and
b
'=2
a
-
b
.
Up:
5.142 (a)
Previous:
5.142 (a), §1
10/04/00 0:28:37