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1.49(c), §3 Solution

Back substitution: From (3'') nothing, then from (2'), y=2+2z, this in (1) to give x=3-2(2+2z)-3z=-1-7z.


Next: 1.49(c), §4 Determinant Up: 1.49(c) Previous: 1.49(c), §2 Elimination
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