Up:
6.47(a)
Previous:
6.47(a), §1 Asked
6.47(a), §2 Solution
The arbitrary vector
can be expressed as
so
So, indeed,
Since
the transformation matrix
Q
from
S
to
E
is
So
So
a
'=-5
a
+3
b
and
b
'=2
a
-
b
.
Up:
6.47(a)
Previous:
6.47(a), §1 Asked
10/02/02 0:18:49
can be expressed as
10/02/02 0:18:49