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![](img9.gif)
Forward elimination is trivial.
Back substitution: x=2y+3z. The solution space is a plane through
the origin:
![](img10.gif)
Vector form:
![](img11.gif)
so that (2,1,0) and (3,0,1) are one possible set of two basis
vector for this plane. A plane is a 2D space.
Next: 12D Example
Up: Null spaces
Previous: 2D Example