In this class,
Note: If for a vector in you define multiplication by a scalar
as
linear spaceproperties, such as
![]() |
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![]() | (1) | ||
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![]() | (2) | ||
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![]() | (3) | ||
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![]() | (4) |
The problem is to show that the vector sets S are
complete.
For a vector space, a multiple of a vector
must still be in the same space. So must the sum of any two vectors
still be in the space. Otherwise the space is not complete. In the
first potential vector space S above, if you multiply a vector of
the form by some constant, you get another vector.
That other vector is only part of S if it can be written as
for some values
and
. If it cannot be
written in this form, the vector is not part of S, and so S is not a
vector space. The same for adding two vectors in S. If you add two
vectors
and
, is the
result of the form
for some
and
?
Otherwise the sum of two vector in S is not in S and S is not a
vector space.
[2, 7.6].