Next: 7.36, §6 Alternate
Up: 7.36
Previous: 7.36, §4 Solve
We need to find the original to

Looking in the tables:

The other factor is a shifted function f, restricted to the interval
that its argument is positive:

With the bar, I indicate that I only want the part of the function for
which the argument is positive. This could be written instead as

where the Heaviside step function H(x)=0 if x is negative and 1 if
it is positive.

Use convolution, Table 6.3, # 7. again to get the product.

This must be cleaned up. I do not want bars or step functions
in my answer.
I can do that by restricting the range of integration to only those
values for which
is nonzero. (Or H is nonzero, if you
prefer)

Two cases now exist:


It is neater if the integration variable is the argument of f. So,
define
and convert:


This allows me to see which physical f values I actually integrate
over when finding the flow at an arbitrary point:

Next: 7.36, §6 Alternate
Up: 7.36
Previous: 7.36, §4 Solve