Derive in terms of and , where are spherical coordinates.
Assume that the surface is given by some relationship
= constant. Use the formulae given earlier in
class for in terms of two parameters and .
The formula requires you to differentiate with respect to
the parameters. Now in spherical,
From class, the derivatives of are
To get the dervatives of , note that certainly, on the surface,
will be some function . To get formulae for its
derivatives, differentiate the constant function :
Write the obtained expression for in terms of the
gradient of F. (The expression for the gradient of F in spherical
coordinates can be found in mathematical handbooks.) Compare with
the Eulerian expression,
as derived in class. Here can be denoted symbolically
as : it is the area of a surface of constant of
dimensions . (In other words, it is the
projection of surface element on a surface of constant .)
What is the equivalent to in your spherical coordinates
expression?
1st Ed: p160, q38, 2nd Ed: p183, q38. Simplify as much as
possible. Sketch each surface, taking the -axis upwards.
Finish finding the derivatives of the unit vectors of the
spherical coordinate system using the class formulae. Then finish
1st Ed p160 q47, 2nd Ed p183 q47, as started in class, by finding
the acceleration. Note that the metric indices for spherical
coordinates are in mathematical handbooks. Also,
Express the acceleration in terms of the spherical velocity
components and their first time derivatives,
instead of time derivatives of position coordinates. Like , etc. This is how you do it in fluid mechanics,
where time-derivatives of particle position coordinates are normally
not used. (So, get rid of the position coordinates with dots on
them in favor of the velocity components.)