2.24 continued. Take the result of the previous homework
question, as posted, and convert the principal part to the Laplacian.
Then get rid of the first order derivatives to get a Helmholtz
equation (with an imaginary ).
2.22b,g. Draw the characteristics very neatly in the -plane,
2.28d expanded. First find a particular solution. Try a
quadratic
But obviously you do not need , nor do you need B to create the
and terms, so take these zero. Next convert the remaining
homogeneous problem for to characteristic coordinates.
Show that the homogeneous solution satisfies
Put, say, . Solve this ODE to find ,
then integrate with respect to to find .
Finally find the complete , in terms of and .
Watch any integration constants; they might not be constants.
2.28f expanded. In this case, leave the inhomogeneous term in
there, don't try to find a particular solution for the original PDE.
Transform the full problem to characteristic coordinates. (I think
it is easiest to leave the logarithms in the coordinates, but you
can try it either way.) Show that the solution satisfies
where indicates the sign of , or
or
or equivalent, depending on exactly how you define the
characteristic coordinates. Solve this ODE for , then
integrate with respect to to find . Write the solution in
terms of and .
Watch any integration constants; they might not be constants.
2.28c. Use the 2D procedure. Show that the equation
may be simplified to
Solve this equation and write the solution in terms of and .
Watch any integration constants; they might not be constants.
2.28k. Reduce the PDE to the form
Now discuss the properly posedness for the initial value problem,
recalling from the class notes that the backward heat equation is
not properly posed. In particular, given an interval
, with an initial condition at some value of
and boundary conditions at and , can the PDE
be numerically solved to find at large ? If is
positive? If is a small negative number? If is a
large negative number?
2.28b. Describe a typical properly posed problem for the
original equation.