Assume that a flow enters a two dimensional duct of constant
area. If no boundary layers developed along the wall, the
centerline velocity of the flow would stay constant. Assuming that
a Blasius boundary layer develops along each wall, what is the
correct expression for the centerline velocity?
Continuing the previous question. Approximate the Blasius
velocity profile to be parabolic up to , and constant from
there on. At what point along the duct would you estimate that
developed flow starts based on that approximation? Sketch the
velocity profile at this point, as well as at the start of the duct
and at the point of the duct where the range
corresponds to of the duct height accurately in a single
graph. Remember the previous question while doing this!
Write down the vorticity for Stokes flow around a sphere. The
velocity field was given in homework question 6.1, and a more
extensive discussion is in section 21.8. Sketch some typical lines
of constant vorticity, in particular , 0.5, 0.75 and
0.99
, where
is the maximum
vorticity. Now compare this very low-Reynolds number vorticity
field with that of high Reynolds number boundary flow. As the
boundary layer solution, you can use the error function profile one
of the previous homework, and assume that
is say
one tenth of the radius. (The fact that it is a cylinder instead of
a sphere makes no important difference here.) You can use the
boundary layer approximation for the vorticity here.
Streamlines for very low Reynolds number, very viscous
Stokes flow look superficially the same as those for high Reynolds
number ideal inviscid flows: both are symmetric front/rear.
But do they really look the same? Plot their streamlines reasonably
accurately. They are given in sections 19.8 and 21.8. You could
use some plotting package to plot them. Alternatively, you could
figure out where the streamlines through the points , 1.5,
1.75, and 2 sphere radii from the center in the symmetry plane end
up far upstream and downstream, and then sketch the streamlines as
well as possible based on that info.