7.6. Do not ignore gravity, but assume the pipe is horizontal.
Do not use the effective pressure. Careful, the gravity vector is
not constant in polar coordinates. Do not ignore the pressure
gradients: assume the pressure can be any function
and derive anything else. Merely assume that
the pressure distribution at the end of the pipe and rod combination
is the same as the one at the start. For the velocity assume
and . Anything else must be derived.
Give both velocity and pressure field.
For the case of question 7.6, what is the force required to pull
the rod through the axis, per unit length? In 7.9, (previous
homework), what is the net downward shear force on the pipe? Does
the simple answer surprise you? Why not?
7.1a Assume only that the velocity only depends on ,
, that
is arbitrary, and that the
pipe is horizontal. Use the effective pressure. Show that two
velocity components must be zero. (You should be able to show that
the effective pressure is independent of from the
appropriate momentum equation by noting that at
must be the same as at ; otherwise just assume it is.
Also note that the velocity can obviously not be infinitely large on
the pipe centerline.)
7.1b Continuing the previous question, derive the velocity and
pressure fields.
7.4. Argue your answer. In what terms would you ballpark the
answer? What is the importance of the pressure level? Of the flow
velocity? What are the relevant values involved? What are the most
important uncertainties? You might want to think of what the right
answer for the head loss would be if there is no flow.