In a real viscous flow at high Reynolds number, a thin boundary layer along the wall upstream of the corner will be unable to withstand much of the adverse pressure gradient slowing it down. So the boundary layer will separate before it reaches the corner, and reattach to the wall downstream of it. Based on that, sketch how you think the viscous streamlines will look like.
Next assume that at the origin the wall bends downwards by 30
degrees, producing a 210 degree corner. Repeat the analysis and
sketching. In this case you should find that there is infinitely
large negative pressure at the corner. The boundary layer
approaching the corner now finds things plain sailing until it
reaches the corner. But right at the corner it is not going to go
around it, as that would produce a very strong adverse pressure
gradient. Instead the boundary layer just keeps going straight
along the -axis immediately behind the corner. That effectively
eliminates the corner and its associated pressure gradient. This
effect is why flows around airfoils with sharp trailing edges and
sufficiently blunted leading edges satisfy the Kutta-Joukowski
condition.
Finally, if the flow is unsteady (i.e. if the constant in your complex potential varies with time), how does that affect whether the ideal flow at the corner has stagnation or infinitely negative pressure?
solidify(replace by a solid body like a cylinder or whatever). To get the body contour accurately, starting streamlines from near the stagnation points can be effective.
cylinder.m
. Print it out and
in the print-out mark where the complex potential for flow around a
circular cylinder is being set. Also mark where the streamlines are
being drawn, and how that works. Run the program in Matlab and
print out the streamlines around a circular cylinder. Then set
variable Gamma
) to an interesting value and print
out those streamlines too.