4.1.2.3 So­lu­tion harmb-c

Ques­tion:

Write out the en­ergy $E_{100}$.

An­swer:

Tak­ing the generic ex­pres­sion

$$E_{n_xn_yn_z} = \frac{2n_x+2n_y+2n_z+3}2\; \hbar\omega$$

and sub­sti­tut­ing $n_x$ $\vphantom0\raisebox{1.5pt}{$=$}$ 1, $n_y$ $\vphantom0\raisebox{1.5pt}{$=$}$ $n_z$ $\vphantom0\raisebox{1.5pt}{$=$}$ 0, you get

$$E_{100} = \frac{5}2\; \hbar\omega$$