EML3100 HW #8 - Fall 1998|
| Due: Tuesday 9/22/98 |
|
Problems:
2.22
2.24
2.25
2.29a
Answers:
2.22: 1W2 = - 12 kJ
2.24: 1W2 = 80.5 kJ
2.25: 1W2 = - 487.7 Btu
2.29a: 1W6 = ~1.14 kJ
Hints:
- Read EACH word.
- Draw some pictures (one for each state).
- Write the given information under each picture.
- Write what it is you are to find.
- Plotting the process on a p-V plot may help...
- Write write the equations you are to use (or might want to use).
- If necessary, find the phase at each state.
- PLEASE try to be organized.