18.2.1.2 Solution stanexl-b

Question:

Derive the Laplace equation for steady heat conduction using vector analysis. Assume Fourier’s law as given in the previous question. In vector form

\begin{displaymath}
\vec q = - k \nabla u
\end{displaymath}

Assume that no heat is added to the solid from external sources.

Answer:

Consider an arbitrary volume $V$ of the solid. The net heat flow out of the volume $V$ per unit time is given by

\begin{displaymath}
Q_{\rm net out} = \int_S \vec q \cdot\vec n { \rm d}S
\end{displaymath}

where $S$ is the outside surface of the volume and $\vec n$ the unit vector normal to the surface element ${\rm d}{S}$.

This heat flux must be zero. If there was net heat flow in or out, the volume would heat up, respectively cool down.

Now use the Gauss-Ostrogradski theorem to convert the surface integral to a volume integral. Then note that if an integrand always integrates to zero, regardless of which volume is integrated over, then that integrand must be zero.

Show that this means that

\begin{displaymath}
\nabla\cdot\vec q = {\rm div} \vec q = 0
\end{displaymath}

Plug in Fourier’s law, and there you have the Laplace equation, assuming that $k$ is constant. (If it is not, you get an equation given in earlier examples.)